珠海比较有名的老中医:一个方程组……要过程…………
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(X+4)/5 - (2Y-3)/3 = 2
(X+3)/3 + (Y+5)/2 = 3
记住!要过程……
(X+3)/3 + (Y+5)/2 = 3
记住!要过程……
3(X+4)-5(2Y-3)=30
2(X+3)+3(Y+5)=18
3X+12-10Y+15=30
2X+6+3Y+15=18
3X-10Y=3
2X+3Y=-3
y=-15/29
x=-21/29
3(X+4)-5(2Y-3)=30
2(X+3)+3(Y+5)=18
3X+12-10Y+15=30
2X+6+3Y+15=18
3X-10Y=3
2X+3Y=-3
Y=-11/15
X=-3/5
3(X+4)-5(2Y-3)=30
2(X+3)+3(Y+5)=18
3X+12-10Y+15=30
2X+6+3Y+15=18
3X-10Y=3
2X+3Y=-3
Y=-11/15
X=-3/5
3(x+4)/15-5(2y-3)/15=30/15
所以,3(x+4)-5(2y-3)=30
下同
3(X+4)-5(2Y-3)=30
2(X+3)+3(Y+5)=18
3X+12-10Y+15=30
2X+6+3Y+15=18
3X-10Y=3
2X+3Y=-3
Y=15/29
X=-21/29