阿文ppt:分式的题目1

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已知 p/x^2-yz = q/y^2-zx = r/z^2-xy ,求证(px+qy+rz)=(x+y+z)*(p+q+r)

设p/x^2-yz = q/y^2-zx = r/z^2-xy =k
p=(x^2-yz)k, q=(y^2-zx)k, r=(z^2-xy)k

p+q+r=(x^2+y^2+z^2-xy-yz-zx)k

px+qy+rz
=(x^2-yz)kx+(y^2-zx)ky+(z^2-xy)kz
=k(x^3+y^3+z^3-3xyz)
=k(x+y+z)(x^2+y^2+z^2-xy-yz-zx)
=(x+y+z)(p+q+r)