chanel香奈儿历史:化简1/7(-2x+3y)(-2x-3y)-10(x+y)^2,x=1.25,y=-0.25
来源:百度文库 编辑:中科新闻网 时间:2024/10/01 12:23:38
x=1.25,y=-0.25
所以x+y=1
1/7(-2x+3y)(-2x-3y)-10(x+y)^2
=1/7[(-2x)^2-(3y)^2]-10*1^2
=1/7(4x^2-9y^2)-10
=1/7[4*(5/4)^2-9*(-1/4)^2]-10
=1/7(25/4-9/16)-10
=(1/7)*(91/16)-10
=13/16-10
=-147/16
-6354/637
化简1/7(-2x+3y)(-2x-3y)-10(x+y)^2,x=1.25,y=-0.25
已知X+Y=-4,求1/2(X+Y)+4(X-Y)-3(X-Y)-3/2(X+Y)-X+Y
规定运算&,使得X&Y=X*X-Y*Y/X*X+Y*Y,则求(-1/2)&(-1/3)
已知1≤ x*x+y*y≤2,如何求证1/2≤x*x+x*y+y*y≤3
1/4(x+y)+1/2(x+y)*(x+y)>=x*根号y+y*根号x
2/(x-y)+x/y-1/x
已知64^2=x^6=8^y,化简:[y(x^2+1/25y)-(x-1/5y)^2-(x+1/5y)^2]÷(-3x)
若x,y ,z满足方程组1、3x+7y-x=3 2、4x+10y-z=2 求X+Y+Z的值
(x-y)^3*(x-y)^2*(y-x)
3X(X-Y)+2Y(X-Y)